General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 3 - Chemical Compounds - Example 3-3 - Using Relationships Derived from a Chemical Formula - Page 77: Practice Example A


18.93 g Br.

Work Step by Step

Grams of Br= $25.00\,mL\,C_{2}HBrClF_{3}\times\frac{1.871\,g\,C_{2}HBrClF_{3}}{1\,mL\,C_{2}HBrClF_{3}}\times\frac{1\,mol\,C_{2}HBrClF_{3}}{197.4\,g\,C_{2}HBrClF_{3}}\times\frac{1\,mol\,Br}{1\,mol\,C_{2}HBrClF_{3}}\times\frac{79.904\,g\,Br}{1\,mol\,Br}$ $=18.93\,g\,Br$
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