General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 27 - Reactions of Organic Compounds - 27-7 Concept Assessment - Page 1248: 27-7

Answer

$\mathrm{CH}_{3} \mathrm{Cl}$ can react with $\mathrm{Cl}$ to form $\mathrm{H}_{2} \mathrm{ClC} ^\cdot$ radical which can react with a $\mathrm{H}_{3} \mathrm{C}^\cdot$ radical to form $\mathrm{ClCH}_{2}\mathrm{CH}_{3}$.

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