Chapter 19 - Spontaenous Change: Entropy and Gibbs Energy - Example 19-9 - Determining the Relationship Between an Equilibrium Constant and Temperature by Using Equations for Gibbs Energy Change - Page 849: Practice Example A

606 K

We find: $\Delta G^{\circ}=\Delta H^{\circ}-T\Delta S^{\circ}=-RT\ln K$ $\implies T=\frac{\Delta H^{\circ}}{\Delta S^{\circ}-R\ln K}$ $=\frac{-114.1\times10^{3}\,J/mol}{-146.5\,Jmol^{-1}K^{-1}-[8.3145\,Jmol^{-1}K^{-1}\times\ln(1.50\times 10^{2})]}$ $=606\,K$