Answer
-1484 kJ
Work Step by Step
We find:
$\Delta G^{\circ}=\Delta H^{\circ}-T\Delta S^{\circ}$
$=(-1648\,kJ)-(298.15\,K\times-0.5493\,kJK^{-1})$
$=-1484\,kJ$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 19 - Spontaenous Change: Entropy and Gibbs Energy - Example 19-5 - Calculating (symbol)G for a Reaction - Page 837: Practice Example A
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