#### Answer

$pH = 11.7$

#### Work Step by Step

1. Find the concentration of NaOH after the dilution:
$C_1 * V_1 = C_2 * V_2$
$ 0.606* 0.125= C_2 * 15$
$ 0.07575 = C_2 * 15$
$C_2 = 0.00505M$
2. Since NaOH is a strong base, $[NaOH] = [OH^-] = 0.00505M$
3. Calculate the pH:
$pOH = -log[OH^-]$
$pOH = -log( 5.05 \times 10^{- 3})$
$pOH = 2.296$
$pH + pOH = 14$
$pH + 2.296 = 14$
$pH = 11.7$