General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 13 - Solutions and Their Physical Properties - Exercises - Percent Concentration - Page 593: 9


A saturated aqueous solution of $NaBr$ at 20$^{\circ}$C contains: $53.7g$ $NaBr$ $/ 100g$ $Solution$

Work Step by Step

1. The mass of the solution, in this is case, is the sum of the NaBr and the water mass. $mass(Solution) = 116g + 100g =216g$ 2. Now we know that there is 116g of NaBr for 216g of solution, and we just need to calculate this for 100 g of solution using a proportion. $\frac{116g}{216g} = \frac{x}{100g}$ $0.537 = \frac{x}{100g}$ $x = 0.537 \times 100g = 53.7g$
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