General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 13 - Solutions and Their Physical Properties - Exercises - Mole Fraction, Mole Percent - Page 593: 31

Answer

(a) $$x_{C_7H_{16}} = 0.187$$ $$x_{C_8H_{18}} = 0.427$$ $$x_{C_9H_{20}} = 0.386$$ (b) $$Mole \space percent \space {C_7H_{16}}=18.7\%$$ $$Mole \space percent \space C_8H_{18}= 42.7\%$$ $$Mole \space percent \space C_9H_{20}= 38.6\%$$

Work Step by Step

(a) $$x_{C_7H_{16}} = \frac{1.28 }{1.28 + 2.92 + 2.64} = 0.187$$ $$x_{C_8H_{18}} = \frac{2.92 }{1.28 + 2.92 + 2.64} = 0.427$$ $$x_{C_9H_{20}} = \frac{2.64 }{1.28 + 2.92 + 2.64} = 0.386$$ (b) $$Mole \space percent \space {C_7H_{16}} = \frac{1.28 }{1.28 + 2.92 + 2.64} \times 100\% = 18.7\%$$ $$Mole \space percent \space = \frac{2.92 }{1.28 + 2.92 + 2.64} \times 100\% = 42.7\%$$ $$Mole \space percent \space = \frac{2.64 }{1.28 + 2.92 + 2.64} \times 100\%= 38.6\%$$
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