General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 13 - Solutions and Their Physical Properties - Example 13-8 - Calculating Osmotic Pressure - Page 579: Practice Example A

Answer

0.857 atm

Work Step by Step

Molarity $M=\frac{\frac{1.50\,g}{342.3\,g/mol}}{0.125\,L}=0.035057\,mol/L$ $\Pi= M\times RT$ $=0.035057\,mol/L\times0.08206\,L\,atm \,K^{-1}mol^{-1}\times298\,K$ $=0.857\,atm$
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