General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Temperature Scales - Page 28: 43

Answer

It is not possible to achieve a temperature of -465 $^{\circ}$F, since this is lower than the absolute zero of temperature.

Work Step by Step

T($^{\circ}$C) = $\frac{5}{9}$ * [T($^{\circ}$F) - 32] T($^{\circ}$C) at -465 $^{\circ}$F: T($^{\circ}$C) = $\frac{5}{9}$ * [-465 - 32] T($^{\circ}$C) = $\frac{5}{9}$ * [-497] T($^{\circ}$C) = -276.1111111 $^{\circ}$C Rounding to 3 significant figures gives -276 $^{\circ}$C -276 $^{\circ}$C is lower than the absolute zero of temperature -273.15 $^{\circ}$C and therefore it is not possible to achieve a temperature of -465 $^{\circ}$F.
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