General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Example 1-5 - Applying Significant Figure Rules: Multiplication/Division - Page 22: Practice Example B

Answer

1.1 $\times$ $10^{6}$

Work Step by Step

We can figure out the appropriate number of significant figures by looking at the number with the least precision, which is 0.000456. Since 0.000456 has three significant figures, the final answer must also be quoted to three significant figures. $\frac{8.21\times10^{4}\times1.3\times10^{-3}}{0.00236\times4.071\times10^{-2}}$ = $1.1\times10^{6}$
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