General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Example 1-4 - Using Percent as a Conversion Factor - Page 17: Practice Example B

Answer

0.857g/mL

Work Step by Step

The mass percent can be used to determine the mass of the 25.0mL sample. mass = 15.0g (from 2-propoanol) $\times$ $\frac{100.0g (from rubbing alcohol}{70.0g (from 2-propanol)}$ = 21.43g rubbing alcohol. Since we know the formula for density is $\frac{mass}{volume}$, then density = $\frac{21.4g}{25.0mL}$ = 0.857g/mL
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