General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Example 1-2 - Relating Mass, Volume, and Density - Page 15: Practice Example b

Answer

2.99 cm

Work Step by Step

$Mass=1.000\,kg=1000\,g$ $Density=8.96\,g/cm^{3}$ $Volume=\frac{Mass}{Density}=\frac{1000\,g}{8.96\,g/cm^{3}}=111.607\,cm^{3}$ $\implies$ Volume $V=\frac{4}{3}\pi r^{3}=111.607\,cm^{3}$ where $r$ is the radius. $\implies r=\sqrt[3] {\frac{3V}{4\pi}}=\sqrt[3] {\frac{3\times111.607\,cm^{3}}{4\pi}}=2.99\,cm$
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