Please see the work below.
Work Step by Step
We know that the absolute values of the electronegativity difference are $C--O\rightarrow 1.0, C--S\rightarrow 0.0, H--Br \rightarrow 0.7$ .Thus $C--O$ is the compound having a more polar bond.
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.