Answer
Please see the work below.
Work Step by Step
We know that
$\lambda=\frac{h}{m\nu}$
We plug in the known values to obtain:
$\lambda=\frac{6.63\times 10^{-34}}{5.313\times 10^{-26}\times 479}=2.603\times 10^{-11}m=26.03pm$
We can compare the wavelength to the length of the molecule as
$\frac{26.03pm}{242pm}\times 100\%=10.75 \%$
