General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 7 - Quantam Theory of the Atom - Questions and Problems - Page 296: 7.73



Work Step by Step

We know that $\nu=\frac{E}{h}$ $\nu=\frac{4.10\times 10^{-19}}{6.626\times 10^{-34}}=6.187\times 10^{14}s^{-1}$ We also know that $\lambda=\frac{c}{\nu}$ $\lambda=\frac{2.998\times 10^8}{6.187\times 10^{14}}=4.845\times 10^{-7}m=484.5nm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.