General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 7 - Quantam Theory of the Atom - Questions and Problems - Page 295: 7.55


$4.6994\times 10^{-19}J$

Work Step by Step

We know that $\nu=\frac{c}{\lambda}$ $\nu=\frac{2.998\times 10^8}{4.227\times 10^{-7}}=7.025\times 10^{14}\frac{m}{s}$ We also know that $E=h\nu $ $E=6.626\times 10^{-34}\times 7.0925\times 10^{14}=4.6994\times 10^{-19}J$
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