General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 6 - Thermochemistry - Questions and Problems - Page 261: 6.63

Answer

Please see the work below.

Work Step by Step

We know that $\frac{-114KJ}{2mol\space NO}\times \frac{1mol\space NO}{30.0g}=-1.90\frac{KJ}{mol}$
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