General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 222: 5.117

Answer

Please see the work below.

Work Step by Step

We know that $P=\frac{nRT}{V}$ $P=\frac{2.080mol \space O_2\times 0.08206(25+273)}{2.50}$ $P=20.34$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.