General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 222: 5.102


Please see the work below.

Work Step by Step

We know that $P=\frac{RT}{(V-b)}-\frac{a}{V^2}$ We plug in the known values to obtain: $P=\frac{0.08206\times (120+273)}{32.50-0.03049}-\frac{5.537}{32.00}$ $P=0.99322-0.00540=0.9878atm$
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