## General Chemistry 10th Edition

$64.11347\frac{g}{mol}$
We know that $PV=nRT$ $\implies n=\frac{PV}{RT}$ $n=\frac{0.862\times 1}{0.0820\times 298}=0.03525mol$ We can find the molar mass as $molar mass=\frac{2.26g}{0.03525mol}=64.11347\frac{g}{mol}$