General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 4 - Chemical Reactions - Questions and Problems - Page 177: 4.152


Please see the work below.

Work Step by Step

We know that $molarity=\frac{moles \space of\space solute }{Liters \space of \space solution}$ $molartiy=\frac{0.024502\space mol\space Na_2SO_4 }{0.0250L}=0.9801M$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.