General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Questions and Problems - Page 124: 3.125


Please see the work below.

Work Step by Step

We know that $175\space$ tablets $\times \frac{68.4\times 10^{-3}}{1 \space tablet}\times \frac{1\space mol\space CaCO_3}{100.09g\space CaCO_3}=0.1196 mol \space CaCO_3$
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