General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Exercises - Page 95: 3.6

Answer

There are 1.2 x $10^{21}$ molecules HCN in 56 mg HCN.

Work Step by Step

We have to convert mass HCN to number of molecules. So the conversion factors needed are two: conversion factor to mol ( 1 mol/Molar mass) and conversion factor to number of molecules ( Avogadro's number/ 1 mol ). First find Molar mass for hydrogen cyanide HCN. Molar mass HCN = 1 x 1.00 + 1 x 12.01 +1x 14.00 Molar mass HCN = 27.01 g/mol or 27.0 g/mol to three significant numbers. Find number of molecules that are in 56 mg HCN ( or 56 x $10^{-3}$g HCN : 56 x $10^{-3}$g HCN x $\frac{1 mol (HCN)}{ 27.0 g (HCN)}$ x $\frac{6.02 \times 10^{23}(HCN molecules)}{1 mol(HCN)}$ = 2.0 x $10^{-3}$mol HCN x $\frac{6.02 \times 10^{23}(HCNmolecules)}{1 mol(HCN)}$ = 12.04 x $10^{20}$ molecules HCN. To three significant numbers 12.0 x $10^{20}$ molecules HCN Therefore 12.0 x $10^{20}$ molecules HCN or 1.2 x $10^{21}$ molecules HCN are in 56 mg HCN.
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