Answer
Please see the explanation below.
Work Step by Step
We know that:
a. The molecules having carbon chains $C_5-C_{11}$ will not be present as they have all boiled off.
b. The molecules having carbon chains greater than $C_{11}$ will be left in the barrel as they boil at a temperature greater than $200^{\circ}C$.
c. We know that the hydrocarbons with low molecular masses will have few polarizable electrons as they have weaker London forces compared to longer chains and thus will boil at low temperature.
d. 2,3-dimethylbutane will boil at a low temperature.
