General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 934: 21.184


Please see the work below.

Work Step by Step

We can find the mass of $LiOH$ as $5.8186mol\space Cl_2\times \frac{1mol\space KClO_3}{ 3mol\space \space mol Cl_2}\times\frac{122.55g\space KClO_3}{1 mol\space KClO_3}=237.69g\times KClO_3$
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