General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 2 - Atoms, Molecules, and Ions - Questions and Problems - Page 79: 2.2

Answer

Please see the work below.

Work Step by Step

We divide each amount of chlorine that is 1.270 g and 1.904 g by the lower amount 1.270 g. Thus, we obtain 1.000 and 1.499 respectively. We convert these whole numbers by multiplying by 2 and get 2.000 and 2.998. The ratio of these amounts of chlorine is 2:3. It is consistent with the law of multiple proportions, as for a fixed mass of iron the masses of chlorine in the other two compounds are in a ratio of small whole numbers.
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