General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 18 - Thermodynamics and Equilibrium - Questions and Problems - Page 773: 18.77

Answer

$\Delta S=-135.95\frac{J}{K}$

Work Step by Step

We know that $\Delta S=\Sigma nS(products)-\Sigma nS(reactants)$ We plug in the known values to obtain: $\Delta S=(159.8+69.95)-(160.7+205.0)$ $\Delta S=-135.95\frac{J}{K}$
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