## General Chemistry 10th Edition

We know that $K_b=\frac{K_w}{K_a}$ $K_b=\frac{1.0\times 10^{-4}}{4.8\times 10^{-13}}=2.08\times 10^{-2}$ As $K_b=\frac{K_w}{K_a}$ $K_b=\frac{1.0\times 10^{-14}}{1.1\times 10^{-12}}=9.09\times 10^{-13}$