Answer
$10.5$
Work Step by Step
We know that
$PH=-logK_a+log\frac{[base]}{[acid]}$
$PH=-log(2.27\times 10^{-11})+log \frac{(0.15)}{(0.20)}=10.5$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 16 - Acid-Base Equilibria - Questions and Problems - Page 704: 16.82
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