Answer
Please see the work below.
Work Step by Step
We know that
$H_3O^{+3}=0.014757M$
We know that
$M_1V_1=M_2V_2$
$V_2=\frac{M_1V_1}{M_2}$
$V_2=\frac{557\times 0.0300}{0.014757}=1132.3ml$
$V_2=1132.3ml\times \frac{1L}{1000ml}=1.13L$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 15 - Acids and Bases - Questions and Problems - Page 662: 15.121
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