General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 15 - Acids and Bases - Questions and Problems - Page 656: 15.14

Answer

$13.60$

Work Step by Step

We know that $PH+POH=PK_w$ $\implies PH+POH=-log(2.5\times 10^{-14})=13.60$
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