Answer
Please see the work below.
Work Step by Step
We know that
$K=\frac{Rate}{C_2H_6N_2}$
We plug in the known values to obtain:
$K=\frac{2.8\times 10^{-6}\frac{M}{s}}{1.13\times 10^{-2}}M$
$K=2.47\times 10^{-4}s^{-1}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 13 - Rates of Reaction - Questions and Problems - Page 582: 13.51
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