General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 13 - Rates of Reaction - Questions and Problems - Page 581: 13.43


Please see the work below.

Work Step by Step

We know that $Rate=\frac{\Delta [NH_4NO_2]}{\Delta t}$ We plug in the known values to obtain: $Rate=\frac{[0.0432M-0.500M]}{[3.00hr-0.00hr]}=2.27\times 10^{-2}\frac{M}{hr}$
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