Answer
Please see the work below.
Work Step by Step
We know that
$S_2=\frac{P_2S_1}{P_1}$
We plug in the known values to obtain:
$S_2=\frac{159mm\space Hg\times 0.0404g\frac{O_2}{L}}{760mm\space Hg}=8.45\times 10^{-3}g\frac{O_2}{L}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 12 - Solutions - Exercises - Page 499: 12.4
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