Answer
The liquid is chloroform.
Work Step by Step
1- Find the density of the liquid:
d = $\frac{m}{V}$
d = $\frac{22.3g}{15.0 mL}$
d = 1.49 $\frac{g}{mL}$ = 1.49 $\frac{g}{cm^{3}}$
2- Compare this density with the known densities of acetone, benzene, chloroform, and carbon tetra-chloride.
The density 1.49 $\frac{g}{cm^{3}}$ is close to the density of chloroform 1.489 $\frac{g}{cm^{3}}$, so the liquid is chloroform.
