Answer
66 x $10^{6}$ worms .
Work Step by Step
Strategy: First convert km to m and apply formula for volume . Then find the number of warms.
1 km = $10^{3}$ m. Therefore we get these figures for the dimensions:
length : 1.00 km or 1.00 x $10^{3}$ m
width: 2.00 km = 2.00 x $10^{3}$ m
and the deep of top soil is 1 m.
Volume = length x width x deep
Volume = 1.00 x $10^{3}$ m x 2.00 x $10^{3}$ m x 1.00 m
Volume = 2 x $10^{6}$ $m^{3}$
There are 33 worms for cubic meter, so to find the number of worms in the above volume we multipy:
2 x $10^{6}$ $m^{3}$ x $\frac{33 (worms)}{m^{3}}$
66 x $10^{6}$ worms