General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 36: 1.92

Answer

66 x $10^{6}$ worms .

Work Step by Step

Strategy: First convert km to m and apply formula for volume . Then find the number of warms. 1 km = $10^{3}$ m. Therefore we get these figures for the dimensions: length : 1.00 km or 1.00 x $10^{3}$ m width: 2.00 km = 2.00 x $10^{3}$ m and the deep of top soil is 1 m. Volume = length x width x deep Volume = 1.00 x $10^{3}$ m x 2.00 x $10^{3}$ m x 1.00 m Volume = 2 x $10^{6}$ $m^{3}$ There are 33 worms for cubic meter, so to find the number of worms in the above volume we multipy: 2 x $10^{6}$ $m^{3}$ x $\frac{33 (worms)}{m^{3}}$ 66 x $10^{6}$ worms
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