Answer
29.8 g of zinc sulfide could be produced by a reaction of 20 g of zinc with sulfur.
Work Step by Step
1- Step one: Apply the law of conservation of mass for the chemical reaction:
m (of zinc) + m (of sulfur) = m (of zinc sulfide)
2- Step two: Replace the mass of zinc, and mass of sulfur:
65.4 g + 32.1 g = m (of zinc sulfide)
m (of zinc sulfide) = 97.5 g
3- Step three: using the law of conservation of mass we found that 65.4 g of zinc would give 97.5 g of zinc sulfide when reacting with sulfur. Than what would be the mass of zinc sulfide that can be produced by reaction of 20 g zinc? Applying the knowledge of law of conservation of mass, we can write:
65.4 g zinc 97.5 g zinc sulfide
20 g zinc unknown g zinc sulfide
4 – Step four: find the mass of zinc sulfide using the above mathematical rule of three :
Unknown mass of zinc sulfide = (20 g x 97.5 g) / 65.4 g
Unknown mass of zinc sulfide = 1,950 g2 / 65.4 g
We find that the mass of zinc sulfide is 29.8 g.
