Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 7 - Problems: 7.43

Answer

3.75 x 10^-36 kg

Work Step by Step

1 Step 1: E = hc/λ h = 6.626 x 10^-34 J*s ; c = 2.998 x 10^8 m/s λ = (589 nm) x (10^-9 m / 1 nm) = 5.89 x 10^-7 m E = (6.626 x 10^-34 J*s)(2.998 x 10^8 m/s) / (5.89 x 10^-7 m) = 3.37 x 10^-19 J 2 Step 2: E = m*c^2, so m = E / c^2 E = 3.37 x 10^-19 J = 3.37 x 10^-19 kg*m^2 / s^2 c = 2.998 x 10^8 m/s m = E / c^2 = (3.37 x 10^-19 kg*m^2 / s^2) / (2.998 x 10^8 m/s)^2 = 3.75 x 10^-36 kg
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