Answer
1.5925 g
Work Step by Step
1
752 torr = 0.989 atm
638 ml = 0.638 liter
128°C = 401°K
Convert the given information
2
nO2 = PV/RT = (0.989*0.638)/((22,4/273)*401) = 0.019 mol
Rearrange PV=nRT and plug in
3
(0.019*2)/3 = 0.013 mol
the ratio between KClO3 and O2 is 2 : 3
4
0.013*122.5
1 mol KClO3 = 122.55 g
