Answer
931.5 MeV
Work Step by Step
We know that one atomic mass unit is defined as 1/12th the mass of an atom of Carbon-12 isotope.
As such
1 amu=1.6606×10−27 kg
Velocity of light c in vacuum is =2.9979×108 ms−1
Using the Einstein's mass energy equivalence relation we get
E=mc2
E=1.6606×10−27×(2.9979×108)2 J
We also know that
1 eV=1 electronic charge in C×1 V=1.60218×10−19 J
Therefore, we get
E=1.6606×10−27×(2.9979×108)21.60218×10−19eV
⇒E=931.5 MeV
, rounded to one decimal place
