Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 24 - Problems - Page 1095: 24.61


See explanation below.

Work Step by Step

a. Given that 3.6 kg laboratory animal receives a single dose of 8.92 Gy Animal received = (8.92 x 10^-4 Gy) (1 rad/0.01 Gy) = 0.0892 rad b. No of joules animal absorb = (0.0892 rad)(0.01 J/kg/ 1rad)(3.6 kg) = 3.2 x 10^-5 J
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