Answer
See explanation below.
Work Step by Step
This answer can be found in the chapter 24 reading.
a. Formation of 241 95Am through b- decay
241 Pu94 --> 241 Am95 + 0 B -1
b. Formation of 228 89Ac through b- decay
228 Ra88 --> 228 Ac89 + 0 B-1
c. Formation of 203 83Bi through alpha decay
207 At85 --> 203 Bi 83 + 4 He2