See explanation below.
Work Step by Step
We know that E cell = - (0.0592 V/n) x ( log Q/ K) and ∆G = -nF Ecell a. If Q / K < 1, then E cell > 0 and ∆G < 0. Q / K = 1, then Ecell = 0 and ∆G = 0. Q / K > 1, then Ecell < 0 and ∆G > 0. b.If Q / K < 1 will the reaction proceed spontaneously