Answer
(a) $CO_2$ concentration increases; $C_3H_8$ and $O_2$ concentrations decrease.
(b) $N_2$ and $H_2O$ concentrations decrease; $NH_3$ and $O_2$ concentrations increase.
Work Step by Step
Decreasing the volume of the container shifts the equilibrium toward the side with less moles of gas.
(a) Reactants: 6 moles of gas; Products: 3 moles of gas.
Products are favored.
$CO_2$ concentration increases; $C_3H_8$ and $O_2$ concentrations decrease.
(b) Reactants: 7 moles of gas; Products: 8 moles of gas.
Reactants are favored.
$N_2$ and $H_2O$ concentrations decrease; $NH_3$ and $O_2$ concentrations increase.
