Answer
5.07 C
Work Step by Step
Moles C10H8 = 5.00 g / 128.17 g/mol = 0.0390
Molality = 0.0390 mol / 0.444 Kg =0.0879
delta T = 4.90 x 0.0879 = 0.431 °C
freezing point = 5.5 - 0.431 = 5.07 °C
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