Answer
a) .944 M C$_{12}$H$_{22}$O$_{11}$
b) .167 M LiNO$_{3}$
Work Step by Step
a) Step 1) 32.3 g C$_{12}$H$_{22}$O$_{11}$ ($\frac{1 mol}{342.3g}$)=.0944 mol C$_{12}$H$_{22}$O$_{11}$)
Step 2) 100 mL ($\frac{1 L}{1000mL}$)= .1 L H$_{2}$O
Step 3) $\frac{.0944 mol C_{12}H_{22}O_{11}}{.100 L}$= .944 M C$_{12}$H$_{22}$O$_{11}$
b) Step 1) 5.8 g LiNO$_{3}$ ($\frac{1 mol}{68.95 g}$)= .0841 g LiNO$_{3}$
Step 2) (505 mL)($\frac{1 L}{1000 mL}$) = .505 L
Step 3) .0841g LiNO$_{3}$/.505 L = .167 M LiNO$_{3}$