Answer
Energy changes in reaction 1
$K → K^{+} + e^{-}$ -418 kJ/mol
$H + e^{-} → H^{-} $ -73 kJ/mol
-48 - 73 = -121 kJ /mol
Energy changes in reaction 2
$K + e^{-} → K^{-} $ 418.8 kJ/mol
$H → H{+} + e^{-}$ 1312 kJ/mol
418.8 + 1312 = 1730.8 kJ/mol
Work Step by Step
Given above.
