Answer
There are 3 possible orbitals with the values:
- $n=2$, $l=1$, $m_l=-1$
- $n=2$, $l=1$, $m_l=0$
- $n=2$, $l=1$, $m_l=1$
Work Step by Step
*NOTES TO REMEMBER:
In an orbital designation,
- the number represents the value of $n$.
- the letter represents the value of $l$, according to the following rule:
$l=0$, the letter used is $s$.
$l=1$, the letter used is $p$.
$l=2$, the letter used is $d$.
$l=3$, the letter used is $f$.
The subshell is $2p$. Therefore, $n=2$ and $l=1$.
For $l=1$, there are 3 possible orbitals corresponding to 3 possible values of $m_l$: $m_l=[-1,0,1]$.