Answer
Photons of UV-B radiation are more energetic than photons of UV-A radiation.
Work Step by Step
According to the formula $$E=h\nu=h\frac{c}{\lambda}$$
we find that $E$ is inversely proportional with $\lambda$.
That means the lower the wavelength of the light, the higher the energy of its photons, and vice versa.
So, since the range of wavelength of UV-B radiation is lower than that of UV-A radiation, photons of UV-B radiation are more energetic than photons of UV-A radiation.
