Answer
3.18g Cu
Work Step by Step
50.0 mL of CuSO4 was added to the calorimeter. Using the molarity of the solution (1.00M), we can convert this into moles of CuSO4 added.
50.0mL / 1000mL = 0.0500 L
(M=mol/L --> mol = M*L)
1.00M*0.0500L = 0.0500 mol CuSO4
Because the mole ratio for CuSO4 to Cu is 1:1, there is therefore 0.0500 mol Cu present in the solution of CuSO4 before mixing. Using the molar mass of Cu (63.55g/mol), we can then calculate the mass of Cu in the solution:
0.0500mol*63.55g/mol = 3.18g Cu
