Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Integrative Exercises - Page 211: 5.115a


3.18g Cu

Work Step by Step

50.0 mL of CuSO4 was added to the calorimeter. Using the molarity of the solution (1.00M), we can convert this into moles of CuSO4 added. 50.0mL / 1000mL = 0.0500 L (M=mol/L --> mol = M*L) 1.00M*0.0500L = 0.0500 mol CuSO4 Because the mole ratio for CuSO4 to Cu is 1:1, there is therefore 0.0500 mol Cu present in the solution of CuSO4 before mixing. Using the molar mass of Cu (63.55g/mol), we can then calculate the mass of Cu in the solution: 0.0500mol*63.55g/mol = 3.18g Cu
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